phpamp;amp;java(二)

例子1:创建和使用你自己的JAVA类
创建你自己的JAVA类非常容易。新建一个phptest.java文件,将它放置在你的java.class.path目录下,文件内容如下:
public class phptest{ /** * A sample of a class that can work with
PHP * NB: The whole class must be public to work, * and of course the
methods you wish to call * directly. * * Also note that from PHP the
main method * will not be called */ public String foo; /** * Takes
a string and returns the result * or a msg saying your string was empty
*/ public String test(String str) { if(str.equals(“”)) { str = “Your
string was empty. “; } return str; } /** * whatisfoo() simply returns
the value of the variable foo. */ public String whatisfoo() { return
“foo is ” + foo; } /** * This is called if phptest is run from the
command line with * something like *java phptest * or *java phptest
hello there */ public static void main(String args[]) { phptest p =
new phptest(); if(args.length == 0) { String arg = “”;
System.out.println(p.test(arg)); }else{ for (int i=0; i args.length;
i++) { String arg = args[i]; System.out.println(p.test(arg)); } } } }
创建这个文件后,我们要编译好这个文件,在DOS命令行使用javac
phptest.java这个命令。
为了使用PHP测试这个JAVA类,我们创建一个phptest.php文件,内容如下: ?php
$myj = new Java(“phptest”); echo “Test Results are b” . $myj-test(“Hello
World”) . “/b”; $myj-foo = “A String Value”; echo “You have set foo to
b”. $myj-foo . “/bbrn”; echo “My java method reports: b” .
$myj-whatisfoo() . “/bbrn”; ?
如果你得到这样的警告信息:java.lang.ClassNotFoundException error
,这就意味着你的phptest.class文件不在你的java.class.path目录下。
注意的是JAVA是一种强制类型语言,而PHP不是,这样我们在将它们融合时,容易导致错误,于是我们在向JAVA传递变量时,要正确指定好变量的类型。如:$myj-foo
= (string) 12345678; or $myj-foo = “12345678”;
这只是一个很小的例子,你可以创建你自己的JAVA类,并使用PHP很好的调用它!

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